4c^3+12c^2-16c=0

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Solution for 4c^3+12c^2-16c=0 equation:


Simplifying
4c3 + 12c2 + -16c = 0

Reorder the terms:
-16c + 12c2 + 4c3 = 0

Solving
-16c + 12c2 + 4c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '4c'.
4c(-4 + 3c + c2) = 0

Factor a trinomial.
4c((-4 + -1c)(1 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(-4 + -1c)' equal to zero and attempt to solve: Simplifying -4 + -1c = 0 Solving -4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1c = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1c = 0 + 4 -1c = 0 + 4 Combine like terms: 0 + 4 = 4 -1c = 4 Divide each side by '-1'. c = -4 Simplifying c = -4

Subproblem 3

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Solution

c = {0, -4, 1}

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